8x^2+8x-329=7

Solution for 8x^2+8x-329=7 equation:

8x^2+8x-329=7

We move all terms to the left:

8x^2+8x-329-(7)=0

We add all the numbers together, and all the variables

8x^2+8x-336=0

a = 8; b = 8; c = -336;
Δ = b2-4ac
Δ = 82-4·8·(-336)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-104}{2*8}=\frac{-112}{16}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+104}{2*8}=\frac{96}{16}
=6
$